PM Modi to unveil ‘Statue of Equality’ in Hyderabad on February 5

Prime Minister Narendra Modi will unveil the ‘Statue of Equality’ today in Hyderabad. The 216 ft tall statue will commemorate the 11th century Bhakti saint Sri Ramanujacharya, who was a philosopher, theologian and social reformer. He was the one who promoted the idea of equality for all, including faith, caste and creed.

More about the grand statue
Made of panchaloha, which is an amalgam of five metals, namely silver, gold, copper, brass, and zync, this statue is one of the tallest metallic statues in the world. The base of the statue is 54 ft high and is named Bhadra Vedi. Sri Chinna Jeeyar Swami of Sri Ramanujacharya Ashram is behind the statue’s conceptualisation.

There are different floors devoted to a vedic digital library and research centre. There are ancient Indian texts, a theatre and an educational gallery too where one can get detailed info on the works of Sri Ramanujacharya, informed the PM office.

About the program
A 3D presentation mapping on the life journey and teachings of the saint will be showcased during the ceremony today. The PM will also visit the identical recreations of 108 divya desams or ornately carved temples surrounding the statue.

The unveiling of the statue is also a part of the ongoing 12-day celebrations of the saint’s 1000th birth anniversary. During his visit, the PM will also inaugurate the International Crops Research Institute for the Semi-Arid Tropics (ICRISAT) climate change research facility.